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il y a 4 heures Thus the rotor speed is n = (1 − s)1000 = 982 r/min part (b): The slip of a 4-pole, 60-Hz motor operating at 1740 r/min is 1800 − 1740 s= = 0.0333 = 3.33% 1800. The rotor currents will therefore be at slip frequency fr = 60 ∗ 0.0333 = 2 Hz. Problem 6.3 part (a): The synchronous speed is clearly 1200 r/min.. Operation speed traduction

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